SOLUTION: Suppose a baseball is shot up from the ground straight up with an initial velocity of 32 feet per second. A function can be created by expressing distance above the ground, s, as

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Question 58644This question is from textbook CPLLEGE ALGEBRA
: Suppose a baseball is shot up from the ground straight up with an initial velocity of 32 feet per second. A function can be created by expressing distance above the ground, s, as a function of time, t. This function is s=-16t2+v0t+s0
* 16 represents 1/2g, the gravitational pull due to gravity (measured in feet per second2)
* v0 is the initial velocity (how hard do you throw the object, measured in feet per second).
* s0 is the initial distance above ground (in feet). If you are standing on the ground, then s0=0
a) What is the function that describes this problem?
b) The ball will be how high above the ground after 1 second?
c) How long will it take to hit the ground?
d) What is the maximum height of the ball? This question is from textbook CPLLEGE ALGEBRA

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Suppose a baseball is shot up from the ground straight up with an initial velocity of 32 feet per second. A function can be created by expressing distance above the ground, s, as a function of time, t. This function is s=-16t2+v0t+s0
* 16 represents 1/2g, the gravitational pull due to gravity (measured in feet per second2)
* v0 is the initial velocity (how hard do you throw the object, measured in feet per second).
* s0 is the initial distance above ground (in feet). If you are standing on the ground, then s0=0
a) What is the function that describes this problem?
so=0 and vo=32
s=-16t^2+32t+0
highlight%28s=-16t%5E2%2B32t%29
:
b) The ball will be how high above the ground after 1 second?
s(1)=-16(1)^2+32(1)
s(1)=-16(1)+32
s(1)=-16+32
highlight%28s%281%29=16ft%29
:
c) How long will it take to hit the ground?
0=-16t^2+32t
0=-16t(t-2)
-16t=0 and t-2=0
-16t/-16=0/-16 and t-2+2=0+2
t=0 and t=2s
t=0 is when it was thrown.
highlight%28t=2s%29 is when it lands.
:
d) What is the maximum height of the ball?
The maximum height occurs halfway through the flight of the ball, it lands at t=2 s. So it's maximum height occurs when t=1. We found out that it was highlight%28s%281%29=16ft%29 on b.
Happy Calculating!!!