# SOLUTION: Monica has three times as many nickels as pennies and twice as many quarters as nickels. In all she has \$3.25. How many coins of each type does she have?

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 Question 571198: Monica has three times as many nickels as pennies and twice as many quarters as nickels. In all she has \$3.25. How many coins of each type does she have?Answer by ankor@dixie-net.com(15657)   (Show Source): You can put this solution on YOUR website!Let n = no. of nickels Let p = no. of pennies Let q = no. of quarters : Write an equation for each statement: : "Monica has three times as many nickels as pennies" n = 3p or divide both sides by 3 p = n : " and twice as many quarters as nickels." q = 2n : "In all she has \$3.25." .01p + .05n + .25q = 3.25 Replace p and q from the 1st two equations .01n + .05n + .25(2n) = 3.25 n + .05n + .50n = 3.25 Multiply by 3 to get rid of the denominators, results: .01n + .15n + 1.5n = 9.75 1.66n = 9.75 n = 5.87, solution has to be an integer, so there something wrong with this problem, a fatal error as they say