SOLUTION: Monica has three times as many nickels as pennies and twice as many quarters as nickels. In all she has $3.25. How many coins of each type does she have?

Question 571198: Monica has three times as many nickels as pennies and twice as many quarters as nickels. In all she has $3.25. How many coins of each type does she have?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Let n = no. of nickels
Let p = no. of pennies
Let q = no. of quarters
:
Write an equation for each statement:
:
"Monica has three times as many nickels as pennies"
n = 3p
or divide both sides by 3
p = n
:
" and twice as many quarters as nickels."
q = 2n
:
"In all she has $3.25."
.01p + .05n + .25q = 3.25
Replace p and q from the 1st two equations
.01n + .05n + .25(2n) = 3.25
n + .05n + .50n = 3.25
Multiply by 3 to get rid of the denominators, results:
.01n + .15n + 1.5n = 9.75
1.66n = 9.75
n = 5.87, solution has to be an integer, so there something wrong with this problem, a fatal error as they say

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