SOLUTION: The ages of three brothers are consecutive even integers. Three times the age of the youngest brother exceeds the oldest brothers age by 48 years. What is the age of the youngest

Question 554392: The ages of three brothers are consecutive even integers. Three times the age of the youngest brother exceeds the oldest brothers age by 48 years. What is the age of the youngest brother?
Answer by Maths68(1474) (Show Source): You can put this solution on YOUR website!
Let
Youngest brother age = x+2
Younger brother age = x+4
Oldest brother age = x+6

Given
-----
Three times the age of the youngest brother exceeds the oldest brothers age by 48 years
3(x+2)=x+6+48
3x+6=x+54
3x-x=54-6
2x=48
2x/2=48/2
x=24

Youngest brother age = x+2 = 24+2 = 26 years old
Younger brother age = x+4 = 24+4 = 28 years old
Oldest brother age = x+6 = 24+6 = 30 years old

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