SOLUTION: if a rocket is launched with an initial velocity of 64 feet per second, its height h(t),in feet, after t second is given by the formula h(t)=64t-16t^2. what is the height of this r

Question 5448: if a rocket is launched with an initial velocity of 64 feet per second, its height h(t),in feet, after t second is given by the formula h(t)=64t-16t^2. what is the height of this rocket after 2 seconds?
thanks for your help!
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!

feet

R^2 at SCC
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