SOLUTION: find 4 consecutive odd integers such that the sum of the second and the fourth is 63 more than one fifth of the third.

Question 536325: find 4 consecutive odd integers such that the sum of the second and the fourth is 63 more than one fifth of the third.

Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
Four consecutive odd integers can be defined as:
x
x+2
x+4
x+6
.
The sum of the second and fourth: x+2 + x+6 = 2x+8.
Is 63 more than 1/5*(x+4).
.
2x+8-63 = 1/5*(x+4)
.
2x -55 = 1/5(x+4)
.
Multiply both sides by 5 to eliminate fraction
.
5(2x -55) = 5/5*(x+4)
.
10x -275 = x + 4
.
9x = 279
.
x = 31
.
So the four consecutive odd integers are: 31, 33, 35, and 37.
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