SOLUTION: Find three consecutive even integers such that the sum of the smallest and the largest is 36.

Question 503590: Find three consecutive even integers such that the sum of the smallest and the largest is 36.
Found 2 solutions by stanbon, lwsshak3:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find three consecutive even integers such that the sum of the smallest and the largest is 36.
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1st: 2x-2
2nd: 2x
3rd: 2x+2
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Equation:
2x-2 + 2x+2 = 36
4x = 36
x = 9
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1st: 2x-2 = 18-2 = 16
2nd: 18
3rd: 20
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Cheers,
Stan H.
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Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find three consecutive even integers such that the sum of the smallest and the largest is 36.
**
let x=smallest even integer
x+2=second consecutive even integer
x+4=third and largest consecutive integer
..
x+(x+4)=36
2x+4=36
2x=36-4=32
x=16
x+2=18
x+4=20
ans:
Three consecutive integers are: 16, 18 and 20
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