SOLUTION: Ming sold a total of 36 red and blue ribbons. She sold 6 more red ribbons than blue ribbons. How many of each color did she sell? We need to know how to put this into an equ

Algebra ->  Human-and-algebraic-language -> SOLUTION: Ming sold a total of 36 red and blue ribbons. She sold 6 more red ribbons than blue ribbons. How many of each color did she sell? We need to know how to put this into an equ      Log On


   

Question 490068: Ming sold a total of 36 red and blue ribbons. She sold 6 more red ribbons than blue ribbons. How many of each color did she sell?
We need to know how to put this into an equation.
Thank you very much for your time.
Tanya
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Ming sold a total of 36 red and blue ribbons. She sold 6 more red ribbons than blue ribbons. How many of each color did she sell?
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Quantity Equation: r + b = 36
Quantity Equation: r = b + 6
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If you want a one-variable equation:
(b+6)+b = 36
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Cheers,
Stan H.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let r = number of red ribbons she sold
Let b = number of blue ribbons she sold
given:
(1) +r+%2B+b+=+36+
(2) +r+=+b+%2B+6+
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You can solve for r and b now
Subtract b from both sides of (2),
then add the equations
(1) +r+%2B+b+=+36+
(2) +r+-+b+=++6+
+2r+=+42+
+r+=+21+
and, since
(1) +r+%2B+b+=+36+
(1) +21+%2B+b+=+36+
(1) +b+=+15+
She sold 21 red ribbons and 15 blue ribbons