Hi
The sum of two numbers is 36
Let x and (36-x)represent the smaller and larger number respectively
Question states***
(1/6)(36-x) + x/9 = 11
Solving for x
3(36-x) + 2x = 11*18
108 - 198 = x
-90 = x, smaller number. Larger number is 126. (36-(-90)
CHECKING our Answer***
(1/6)126 - 10 = 21 - 10 = 11