SOLUTION: If the sum of 2 numbers is -14 and their product is 32, what are the numbers? Let x = one number Let x - 14 = the other number x(x - 14) = 32 x^2- 14x + 32 (x - 6) (x-8)

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Question 396646: If the sum of 2 numbers is -14 and their product is 32, what are the numbers?
Let x = one number
Let x - 14 = the other number
x(x - 14) = 32
x^2- 14x + 32
(x - 6) (x-8)
The two numbers are -8 and -6
I know that -8 + -6 = -14 but when I plug in the numbers that do not equal 32. What am I not doing correct?
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
If the sum of 2 numbers is -14 and their product is 32, what are the numbers?
Let x = one number
Let x - 14 = the other number
x(x - 14) = 32
x^2- 14x + 32
(x - 6) (x-8)
The two numbers are -8 and -6
I know that -8 + -6 = -14 but when I plug in the numbers that do not equal 32. What am I not doing correct?
-------------------------
Let x = one number
Let -14 - x = the other number
x(-x - 14) = 32
-x^2 - 14x - 32 = 0
x^2 + 14x + 32 = 0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=68 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: -2.87689437438234, -11.1231056256177. Here's your graph:

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x = -7 ± sqrt(17)
One number is -7 + sqrt, the other is -7 - sqrt
No integer solutions.
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I would check for a typo.
If the sum is -12, then it's -4 and -8.
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