SOLUTION: if ten times the smaller of two consecutive integers is added to six times the larger, the result is 118. Find the integers.

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Question 377728: if ten times the smaller of two consecutive integers is added to six times the larger, the result is 118. Find the integers.

Answer by robertb(5830)   (Show Source): You can put this solution on YOUR website!
10x + 6(x+1) = 118.
10x + 6x + 6 = 118.
16x = 112.
x = 7, the smaller integer,
x + 1 = 8, the larger integer.

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