SOLUTION: two children cross a startin line at the same time, one running with a velocity of +3.5m/s and the other with a velocity of -4.0m/s. how far apart are they after 12 s?
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Question 356477: two children cross a startin line at the same time, one running with a velocity of +3.5m/s and the other with a velocity of -4.0m/s. how far apart are they after 12 s?
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
3.5*12=42
-4.0*12=-48
42-(-48)=|90|=90 m
.
Ed
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