SOLUTION: the perimeter of a rectangular lot is 190 ft. the width of the lot is 15ft more than the length. what are the dimensions of the lot.
P=2L+2W
W=L+15
190=2L+2(L+15)
190=2L+2L+
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Question 337467: the perimeter of a rectangular lot is 190 ft. the width of the lot is 15ft more than the length. what are the dimensions of the lot.
P=2L+2W
W=L+15
190=2L+2(L+15)
190=2L+2L+30
190-30=4L
160/4=L
40=L
W=40+15=55
DIMENSIONS IS 55 FEET BY 40 FEET.
Answer by chiexpert(48) (Show Source): You can put this solution on YOUR website!
P=2L+2W
W=L+15
190=2L+2(L+15)
190=2L+2L+30
190-30=4L
160/4=L
40=L
W=40+15=55
DIMENSIONS IS 55 FEET BY 40 FEET.
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