SOLUTION: The sum of three numbers is -48 the first is 12 more than the second number, and the third number is 20 less than twice the second number find the three numbers
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Question 330010: The sum of three numbers is -48 the first is 12 more than the second number, and the third number is 20 less than twice the second number find the three numbers
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The sum of three numbers is -48
x + y + z = -48
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the first is 12 more than the second number
x = y+12
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the third number is 20 less than twice the second number
z = 2y-20
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find the three numbers
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Substitute for x and z and solve for "y":
y+12 + y + 2y-20 = -48
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4y - 8 = -48
4y = -40
y = -10
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Since x = y+12, x = 2
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Since z = 2y-20 = -40
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Cheers,
Stan H.
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