SOLUTION: The velocity ds/dt (in meters/second) of a projectile is given by
ds/dt=-9.8t+16
Find the displacement s of the object after 4 seconds if the initial displacement is 48 m
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Question 328500: The velocity ds/dt (in meters/second) of a projectile is given by
ds/dt=-9.8t+16
Find the displacement s of the object after 4 seconds if the initial displacement is 48 m.
Found 2 solutions by Alan3354, Fombitz:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The velocity ds/dt (in meters/second) of a projectile is given by
ds/dt=-9.8t+16
Find the displacement s of the object after 4 seconds if the initial displacement is 48 m.
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s = the integral of ds/dt
s = -4.9t^2 + 16t + C
C = 48 m, the initial displacement
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s(t) = -4.9t^2 + 16t + 48
s(4) = -4.9*16 + 64 + 48
s(4) = 33.6 meters
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Integrate,
.
.
.
m
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