SOLUTION: A vendor sells hot dogs and bags of potato chips. The first customer buys 3 hot dogs and 5 bags of chips and pays $14.74. The second customer buys 2 hot dogs and 2 bags of chips an
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Question 324049: A vendor sells hot dogs and bags of potato chips. The first customer buys 3 hot dogs and 5 bags of chips and pays $14.74. The second customer buys 2 hot dogs and 2 bags of chips and pays $7.50. What is the price for each hot and each bag of chips?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A vendor sells hot dogs and bags of potato chips. The first customer buys 3 hot dogs and 5 bags of chips and pays $14.74. The second customer buys 2 hot dogs and 2 bags of chips and pays $7.50. What is the price for each hot and each bag of chips?
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Equations:
3h + 5c = 14.74
2h + 2c = 7.50
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Multiply 1st Eq. by 2
Multiply 2nd Eq. by 3
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6h + 10c = 29.48
6h + 6c = 22.50
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Subtract 2nd from 1st.
4c = 6.98
c = $1.75 (cost of an order of chips)
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Since 2h+2c = 7.50
2h + 2(1.75) = 7.50
2h = 4
h = $2.00 (cost of a hot dog)
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Cheers,
Stan H.
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