SOLUTION: Greetings, Francois went 36 miles downstream and returned. The round trip took 5+1/4 (5.25) hours. Find the speed of the boat in still water and the speed of the current if the

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Question 318363: Greetings,
Francois went 36 miles downstream and returned. The round trip took 5+1/4 (5.25) hours. Find the speed of the boat in still water and the speed of the current if the speed of the current is 1/7 the speed of the boat.
Thank you in advance for any assistance, have a great week!

Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
Francois went 36 miles downstream and returned.
The round trip took 5+1/4 (5.25) hours. Find the speed of the boat in still
water and the speed of the current if the speed of the current is 1/7 the speed of the boat.
:
Let s = speed of boat in still water
then
s = speed of the current
:
The current is added and subtracted from the boat speed so we can say:
s = speed downstream
and
s = speed upstream
:
Write a time equation, time = dist/speed
+ = 5.25
invert the dividing fractions and multiply
+ = 5.25
:
+ = 5.25
multiply by 24s to eliminate the denominators
4(252) + 3(252) = 5.25(24s)
:
1008 + 756 = 126s
:
s =
s = 14 mph is the speed of the boat in still water
then
*14 = 2 mph is speed of the current
:
:
See if this is true
36/16 + 36/12 =
2.25 + 3 = 5.25 hrs; confirms our solutions

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