SOLUTION: Bob ate 4 fewer than twice as many doughnuts as Ethan. Between the two, they ate a total of 32 doughnuts. How much did each boy eat?
Algebra.Com
Question 284977: Bob ate 4 fewer than twice as many doughnuts as Ethan. Between the two, they ate a total of 32 doughnuts. How much did each boy eat?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
d+2d-4=32
3d=32+4
3d=36
d=36/3
d=12 number of doughnuts eaten by Ethan
2*12-424-4=20 number of doughnuts eaten by Bob.
Proof:
12+24-4=32
12+20=32
32=32
RELATED QUESTIONS
Jesse and Larry entered a pie eating contest. Jesse ate 5 less than twice as many pies as (answered by ewatrrr)
Kim's brother ate 9 of her muffins.that was 3/8 of her doughnuts. How many doughnuts did... (answered by josmiceli,Alan3354)
Over the last 4 Sundays, I have consumed a total of 32 cinnamon rolls. I ate the most on... (answered by Theo)
On the first day of a two day meeting, 10 coffees and 10 doughnuts were purchased for a... (answered by ikleyn)
Dolores ate 3 more than Dimpy. If they ate a total of 30 pies in all, how many did each... (answered by stanbon)
My homework isnt hard a lot of the time, but this problem is REALLY stumping me! Any... (answered by josmiceli)
Quinn, Rhonda, and Sue shared 3/4 of a whole pizza. Quinn was hungrier than Rhonda and... (answered by josmiceli)
Help I can't figure this one out. Angela did 5 fewer than twice as many sit-ups as... (answered by ankor@dixie-net.com)
Together, Alex and Mimi ate 12 pieces of chocolate. Alex ate twice as much as Mimi. How (answered by ewatrrr)