# SOLUTION: Beaker A contains 1 liter which is 15 percent oil and the rest is vinegar, thoroughly mixed up. Beaker B contains 2 liters which is 40 percent oil and the rest vinegar, completely

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 Question 275345: Beaker A contains 1 liter which is 15 percent oil and the rest is vinegar, thoroughly mixed up. Beaker B contains 2 liters which is 40 percent oil and the rest vinegar, completely mixed up. Half of the contents of B are poured into A, then completely mixed up. How much oil (in liters)should now be added to A to produce a mixture which is 60 percent oil? i dont even know where to begin!! any help would be really appreciated :)Answer by stanbon(57347)   (Show Source): You can put this solution on YOUR website!Beaker A contains 1 liter which is 15 percent oil and the rest is vinegar, thoroughly mixed up. Oil = 0.15*1 = 0.15 liter ; total = 1 liter --------------------------------- Beaker B contains 2 liters which is 40 percent oil and the rest vinegar, completely mixed up. Oil = 0.40*2 = 0.80 liter ; total = 2 liter --------------------------------- Half of the contents of B are poured into A, then completely mixed up. That half contains 0.40 liter of oil ; total = 2 liter --------------------------------- How much oil (in liters)should now be added to A to produce a mixture which is 60 percent oil? --- Equation: oil + oil = oil 0.40 + x = 0.60(2 + x) Multiply thru by 100 to get: 40 + 100x = 60*2 + 60x 40x = 80 x = 2 liters (amount of oil that must be added) ====================================================== Cheers, Stan H.