SOLUTION: A hospital needs 80 L of a 12% solution of disinfectant. How many liters of a 33% solution and a 5% solution should be mixed to obtain this 12% solution?
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Question 257394: A hospital needs 80 L of a 12% solution of disinfectant. How many liters of a 33% solution and a 5% solution should be mixed to obtain this 12% solution?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
.33x+(80-x)*.05=.12*80
x=20
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