SOLUTION: I was wondering how you turn a word problem into an algebra equation. ex1.1.) The total receipts for a basketball game are $1400 for 788 tickets sold. Adults paid $2.50 for admiss

Question 255123: I was wondering how you turn a word problem into an algebra equation.
ex1.1.) The total receipts for a basketball game are $1400 for 788 tickets sold. Adults paid $2.50 for admission and students paid $1.25. How many of each kind of tickets were sold?
If x is how many of each kind of tickets were sold i was wondering how you put it in an equation.

Thank you.
Found 2 solutions by richwmiller, ankor@dixie-net.com:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
I would not use x for how many of each kind.
I would use a for number of adult tickets
and s for student tickets
What they really want is how many adult and how many student tickets since we know the total is 788.
a+s=788
s=788-a
2.50a+1.25s=1400
you can substitute 788-a for s
2.50a+1.25(788-a)=1400
Now we have one unknown in one equation

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The total receipts for a basketball game are $1400 for 788 tickets sold.
Adults paid $2.50 for admission and students paid $1.25.
How many of each kind of tickets were sold?
If x is how many of each kind of tickets were sold.
:
You have to decide which type of ticket is represent by x:
Let x = no. of adult tickets
The total number of tickets sold is given as 788, therefore
(788-x) = no. of student tickets
:
The revenue equation
2.50x + 1.25(788-x) = 1400
:
Solve this equation and you have the number of adult tickets, then (788-x) = no. of student tickets
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