# SOLUTION: a campground rents campsites for \$12 per night. at this rate, all 90 campsites are usually rented. for each \$1 increase in the price per night, about 3 less sites are rented. the c

Algebra ->  Algebra  -> Human-and-algebraic-language -> SOLUTION: a campground rents campsites for \$12 per night. at this rate, all 90 campsites are usually rented. for each \$1 increase in the price per night, about 3 less sites are rented. the c      Log On

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 Question 252504: a campground rents campsites for \$12 per night. at this rate, all 90 campsites are usually rented. for each \$1 increase in the price per night, about 3 less sites are rented. the campground's nightly revenue can be modeled by R=(90-3x)(12+x). use the vertex form to find how the campground can maximize nightly revenueAnswer by stanbon(57307)   (Show Source): You can put this solution on YOUR website!R=(90-3x)(12+x). use the vertex form to find how the campground can maximize nightly revenue ---------- R(x) = -3x^2-36x+90x+12*90 R(x) = -3x^2+ 54x + 1080 ----------------- Convert to vertex form by completing the square: R(x)-1080-3*? = -3(x^2-18x+?) R(x)-1080-3*81 = -3(x^2-18x+81) R(x)-1323 = -3(x-9)^2 --- Vertex: (9,1323) Increase the price by \$9; Revenue will be \$1323. Cheers, Stan H.