SOLUTION: the perimeter of a rectangle garden is 76 ft. the length is six feet less than three times the width. find the dimensions of the garden

Question 164763: the perimeter of a rectangle garden is 76 ft. the length is six feet less than three times the width. find the dimensions of the garden
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
The Perimeter P = 2(length(L)) + 2(width(W)) Now we are given that L = 3W-6 and that the perimeter =76ft so plugging in known values we have 76 = 2(3W-6)+ 2W solving for the width W... 76 = 6W-12+2W simplifying further by adding 12 to each side and combining like terms we arrive at 88 = 8W. divide each side by 8 and you conclude that W=11 Now since L=3W-6 we have 3(11)-6 which equals 27
Answer W=11
L=27
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