SOLUTION: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $1
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Question 153324: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have?
Answer by mangopeeler07(462) (Show Source): You can put this solution on YOUR website!
d=number of dimes
n=number of nickels
coefficient= value of the coin
value of dime(number of dimes)+value of nickel(number of nickels)=total value
10(d)+5(n)=565
10(2d)+5(n+8)=1045------------If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45.
Distribute
20d+5n+40=1045
Subtract 40 from both sides
20d+5n=1005
and
10d+5n=565 both have 5n, so subtract them from each other
10d=440
Divide both sides by 10
d=44
Number of dimes=44
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