SOLUTION: Complete the square and write the equation in standard form. Then give the center and radius of the circle. x2 + y2 - 2x - 4y

SOLUTION: Complete the square and write the equation in standard form. Then give the center and radius of the circle. x2 + y2 - 2x - 4y - 4 = 0

Question 152653: Complete the square and write the equation in standard form. Then give the center and radius of the circle.
x2 + y2 - 2x - 4y - 4 = 0

Answer by mducky2(62) (Show Source): You can put this solution on YOUR website!
It's easier to start by separating the x's from the y's:

In order to complete the square, we can use this equation:

Now let's make the x's fit into this equation:

We know that b = -2. But make sure to subtract whatever you add on so that everything adds up back in the original formula:

Now let's make the y's fit into this equation:

We know that b = -4

Putting everything back into the original equation, we can now write it in standard form:

Moving all the excess numbers to the side:

The center of a circle (h,k) and the radius r can be found using this equation:

Back to the equation:

It looks like h = -1 and k = 4. Therefore the center of the circle is (-1,4).

It also looks like r² = 9. Let's solve for r:

Therefore, the radius of the circle is 3.

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