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put this solution on YOUR website!Find three consecutive odd integers such that the sum of three times the first and twice the second is 26 more than three times the third ?
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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3(2x-1)+2(2x+1) = 3(2x+3)+26
6x-3 + 4x+2 = 6x+9+26
10x -1 = 6x + 35
4x = 36
x = 9
1st: 2x-1 = 17
2nd: 19
3rd: 21
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Cheers,
Stan H.