SOLUTION: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $1
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-> SOLUTION: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $1
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Question 143063: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! N=number of nickels
D=number of dimes
So 5N+10D=565
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If:
10(D*2)+5(N+8) = 1045, or 20D+5N+40 = 1045
2 equations in 2 unknowns.
5N+10D=565 eqn 1
5N+20D=1005 eqn 2
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Subtract eqn 2 from eqn 1
-10D = -440
D = 44, the number of dimes
Sub D=44 into either eqn, and find that N=25
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Joe must be VERY proud to have 44 dimes and 25 nickels. Jeez.
