SOLUTION: four oranges and five apples cost $3.56. three oranges and four apples cost $2.76. find the cost of an orange and the cost of an apple.

Question 132676This question is from textbook Algebra 1
: four oranges and five apples cost $3.56. three oranges and four apples cost $2.76. find the cost of an orange and the cost of an apple. This question is from textbook Algebra 1

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
four oranges and five apples cost $3.56. three oranges and four apples cost $2.76. find the cost of an orange and the cost of an apple.
-----------------
EQUATIONS:
4R + 5A = 3.56
3R + 4A = 2.76
------------------
Multiply 1st by 3 and 2nd by 4 to get:
12R + 15A = 3*3.56
12R + 16A = 4*2.76
--------------------
Substract 1st from 2nd to get:
A = 0.36 (price of an apple)
Substitute to solve for R:
4R + 5*0.36 = 3.56
4R = 1.76
R = 0.44 (prince of an orange)
===================================
Cheers,
Stan H.
RELATED QUESTIONS
four oranges and five apples cost $2:00. three oranges and four apples cost $1.56. find... (answered by mananth)

four oranges and five apples cost $3.56. Three oranges and four apples cost $2.76. find... (answered by jainenderkapoor)

four oranges and five apples cost $3.56. Three oranges and four apples cost $2.76. find... (answered by Abbey)

four oranges and five apples cost $3.56 three oranges and four apples cost $2.76. find... (answered by Abbey)

Four oranges and five apples cost $2.00. Three oranges and four apples cost $1.56. Find... (answered by checkley71)

four oranges and five apples cost $3.56.three oranges and four apples cost $2.76.find... (answered by checkley71,MathLover1)

Four oranges and five apples cost $2.00. Three oranges and four apples cost $1.56. Find... (answered by stanbon)

Four oranges and five apples cost $3.56. Three oranges and four apples cost $2.76. Find... (answered by mananth,JBarnum)

Four oranges and five apples cost 3.56$. Three oranges and four apples cost 2.76$. Find... (answered by nyc_function)