SOLUTION: Hello can someone please try and solve these problems, i would greatly appericiate it!! J. Rivera. 1) State the domain of the following: a){{{g(x)=sqrt

Question 125279: Hello can someone please try and solve these problems, i would greatly appericiate it!!
J. Rivera.
1) State the domain of the following:
a)
Answer:
b)
2x+1 OVER x-s
Answer:
c) h(x)=3x^2+5x-3
Answer:
d) l(x)-2x+3
Answer:
e) m(x)=3/x^2-7 m "3 OVER x^2-7"
Answer:
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Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
1) State the domain of the following:
a)
Answer:
you know that has to be positive
Therefore if the result would be a inside the radical which is .
so, the domain would be to (0 is allowed)
Interval notation [, )

b)
Answer:
denominator cannot be equal to ; so, if we will have to divide by which doesn't make a sense.
if ...then
the domain would be to and from to
Interval notation (, ] U (, ]

c) h(x)=3x^2+5x-3
Answer:
first find square roots

Solved by pluggable solver: Quadratic Formula

Let's use the quadratic formula to solve for x:

Starting with the general quadratic

the general solution using the quadratic equation is:

So lets solve ( notice , , and )

Plug in a=3, b=5, and c=-3

Square 5 to get 25

Multiply to get

Combine like terms in the radicand (everything under the square root)

Simplify the square root (note: If you need help with simplifying the square root, check out this solver)

Multiply 2 and 3 to get 6

So now the expression breaks down into two parts

or

Now break up the fraction

or

Simplify

or

So the solutions are:

or

the domain would be to and from to
Interval notation (, ] U [, )
or
the domain would be to and from to
Interval notation (, ] U [, )

d) l(x)= -2x+3

Answer:
(, )
e) m(x)=3/x^2-7 m "3 OVER x^2-7"
Answer:
cannot be equal to ; ... ......
the domain would be to and from to
Interval notation (, ] U [, )

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