SOLUTION: I'm sorry I lefted this out. Please help
Use the graph of y=x^2+4x-5 to answer the following.
Using the graph, what are the solution(s) to the equation x^2+4x-5=0
Explain how
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Question 120083: I'm sorry I lefted this out. Please help
Use the graph of y=x^2+4x-5 to answer the following.
Using the graph, what are the solution(s) to the equation x^2+4x-5=0
Explain how you obtain your answer(s) by looking at the graph
Does this function have a maximum or a minimum?
Explain how you obtain your answer(s) by looking at the graph
What are the coordinates of the vertex in (x, y) form?
What is the equation of the line of symmetry for this graph?
Thank you
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Use the graph of y=x^2+4x-5 to answer the following.
---------------------
Using the graph, what are the solution(s) to the equation x^2+4x-5=0
x=-5, x=1
------------------
Does this function have a maximum or a minimum?
Ans: minimum
----------------
What are the coordinates of the vertex in (x, y) form?
x=-b/2a = -4/2 = -2 ; y = (-2)^2+4*-2-5 = -9
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What is the equation of the line of symmetry for this graph?
x = -2
===============
Cheers,
Stan H.
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