SOLUTION: Could you please solve this equation for me.
Suppose that the width if a rectangle is 5 inches shorter than the length and tha perimeter of the rectangle is 50. What is the w
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Question 119916This question is from textbook Blitzer College Algebra
: Could you please solve this equation for me.
Suppose that the width if a rectangle is 5 inches shorter than the length and tha perimeter of the rectangle is 50. What is the width? Could you please show you work so I can get a better understanding? Thanks
This question is from textbook Blitzer College Algebra
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
You can start with the formula for the perimeter of a rectangle:
where L = length and W = width.
The problem states that the width, W, is 5 inches shorter than the length, L.
You write this as:
but since we are looking for the width, W, we'll rewrite this as:
The perimeter, P, is given as 50, so
Now we'll substitute these values into the formula above and solve for W.
Substitute
Combine like-terms.
Apply the distributive property.
Substitute P = 50.
Subtract 10 from both sides.
Finally, divide both sides by 4.
The width is 10 inches.
The length is 15 inches.
Check:
Substitute L= 15 and W = 10
The solution is good!
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