Let units digits be U Then tens digit = U + 3, and hundreds digit is: 2T, or 2(U + 3) = 2U + 6 By observation, with the hundreds digit being 2U + 6, U or the units digit CANNOT be 2 or more. Therefore, U or the units digit MUST either be 0 or 1. First case: Units digit = 0Tens digit = 0 + 3 = 3 Hundreds digit = 2(0) + 6 = 6 Number, based on the above: