SOLUTION: A hot bar of iron at 1100 degrees Fahrenheit is quenched in oil at 350 degrees. After 2 minutes, the temperature of the iron is 750 degrees.
(a) Find the value for k in Newton's
Algebra ->
Human-and-algebraic-language
-> SOLUTION: A hot bar of iron at 1100 degrees Fahrenheit is quenched in oil at 350 degrees. After 2 minutes, the temperature of the iron is 750 degrees.
(a) Find the value for k in Newton's
Log On
Question 1176057: A hot bar of iron at 1100 degrees Fahrenheit is quenched in oil at 350 degrees. After 2 minutes, the temperature of the iron is 750 degrees.
(a) Find the value for k in Newton's Law of Cooling. Round your answer to the nearest thousandth.
k = ?
(b) What will the temperature of the iron be after 10 minutes? Round your answer to the nearest degree.
? degrees Fahrenheit
(c) How long will it take for the iron to reach 400 degrees? Round your answer to the nearest tenth of a minute.
? minutes Answer by ewatrrr(24785) (Show Source):
Hi
After 2 minutes, the temperature of the iron is 750 degrees.
T(t)=Ae^kt + Ts
t is time
•A is the difference between the initial temperature of the object and the surroundings (1100-350)
•k is a constant, the continuous rate of cooling of the object
T(2) = 750
750=750e^2k + 350
400 = 750e^2k
ln(400/750)/2 = k = -.314
(b) What will the temperature of the iron be after 10 minutes?
T=750e^-3.14 + 350 = 382degrees
(c) How long will it take for the iron to reach 400 degrees?
400=750e^(-.314)t + 350
ln(50/750)/-.314 = t = 8.6 min
Wish You the Best in your Studies.