SOLUTION: a tank containing 50 liter of water develops a leak and loses water at a constant rate. after 20 minutes it contain 40 liters. after a further 30 minutes the tank is 5% of its full

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Question 1170092: a tank containing 50 liter of water develops a leak and loses water at a constant rate. after 20 minutes it contain 40 liters. after a further 30 minutes the tank is 5% of its full capacity. determine the original capacity
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Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
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containing 50 liter of water develops a leak and loses water at a constant rate. after 20 minutes it contain 40 liters
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Points (0,50) and (20,40)

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after a further 30 minutes the tank is 5% of its full capacity.
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Point (50,0.05c), using c as the tank's capacity
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Answer by ikleyn(52783)   (Show Source): You can put this solution on YOUR website!
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I solved this problem completely several days ago under this link

https://www.algebra.com/algebra/homework/Finance/Finance.faq.question.1169752.html


For your convenience, I copy and paste that solution one more time here again. 


From first two sentences, we have this equation

    V(t) = 50 - a*t.


representing the current volume V(t) as a function of time, t, in minutes,

and "a" is the constant leaking rate in liters per minute.



At t= 20 minutes,  

    V(20) = 40 = 50 - a*20,


which gives  a =  =  = 0.5  liters per minute.



After further 30 minutes,  the volume of the water in the tank is

    V(50) = 40 - 0.5*30 = 40 - 15 = 25 liters.


So, 25 liters is 5% of the tank capacity.



Hence, the total capacity of the tank is   = 500 liters.



ANSWER.  The total capacity of the tank is   = 500 liters.

Solved,  answered,  explained and completed.



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