SOLUTION: A woman is 5 years older than her husband and 10 times as old as their daughter. In 14 years, the sum of their ages will be 100. How old is each one now?

Question 1161065: A woman is 5 years older than her husband and 10 times as old as their daughter. In 14 years, the sum of their ages will be 100. How old is each one now?
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

Let x be the daughter's age.
Then the woman's age is 10x. (10 times the daughter's age)
Then the man's age is 10x-5. (the woman is 5 years older than him)

If the sum of their ages 14 years from now will be 100, then the sum of their current ages is 100-3(14) = 100-42 = 58.

So

Solve using basic algebra....

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