SOLUTION: A-5 On an oblique triangle solve a=96in., b=58 in., B=30 degrees.
I know the answer is A=55.9 degrees, C=94.1 degrees, c=116 in, but I cannot get it to come out right. I sure woul
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Question 112950This question is from textbook Mathematics for the Trades
: A-5 On an oblique triangle solve a=96in., b=58 in., B=30 degrees.
I know the answer is A=55.9 degrees, C=94.1 degrees, c=116 in, but I cannot get it to come out right. I sure would appreciate help. THANKS
This question is from textbook Mathematics for the Trades
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
a=96in., b=58 in., B=30 degrees
.
sinB/b=sinA/a
sin(30)/58=sin(A)/96
sin(A)=96*sin(30)/58=24/29
sin^-1(24/29)=55.85 deg for angle A
180-(55.85+30)=180-85.85=94.15 deg angle C
.
c/sin(94.15)=58/sin(30)
c=sin(94.15)*58/sin(30)=115.70
.
Ed
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