SOLUTION: If a ball is thrown straight up from the top of a building that is 407 feet high, the position in feet above the ground is given by the function s(t) = -16t^2 + 75t + 407 where t

Question 1115031: If a ball is thrown straight up from the top of a building that is 407 feet high, the position in feet
above the ground is given by the function s(t) = -16t^2 + 75t + 407 where t is the number of
seconds elapsed.
a. How high is the projectile after 3 seconds?
b. How long will it take for the ball to reach a height of 450 feet above the ground?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
If a ball is thrown straight up from the top of a building that is 407 feet high, the position in feet
above the ground is given by the function s(t) = -16t^2 + 75t + 407 where t is the number of
seconds elapsed.
a. How high is the projectile after 3 seconds?
Sub 3 for t.
---------------------
b. How long will it take for the ball to reach a height of 450 feet above the ground?
s(t) = -16t^2 + 75t + 407 = 450
Solve for t.
The smaller value is ascending, the greater is descending.

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