Question 1097585: Mary and Murray travel respectively at x and y km/h heading directly towards each other across a distance of 960 km. If both start at 10 am they will meet at 3 pm. If Murray starts at 6 am and Mary starts at 10 am they will meet at noon. Find (x,y)
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(53763)   (Show Source):
You can put this solution on YOUR website! .
Mary and Murray travel respectively at x and y km/h heading directly towards each other across a distance of 960 km.
If both start at 10 am they will meet at 3 pm. If Murray starts at 6 am and Mary starts at 10 am they will meet at noon. Find (x,y)
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First condition, "If both start at 10 am they will meet at 3 pm." means that
5x + 5y = 960 kilometers (1) (they cover the distance in 5 hours, from 10 am to 3 pm)
The second condition "If Murray starts at 6 am and Mary starts at 10 am they will meet at noon." means
6x + 2y = 960 (2) (Murray is on the way during 6 hours, while Mary is on the way only 2 hour before they meet each other)
So, you have this system of 2 equations in 2 unknown
5x + 5y = 960,
6x + 2y = 960,
which you can easily solve by any method.
Answer by MathTherapy(10809)  (Show Source):
You can put this solution on YOUR website!
Mary and Murray travel respectively at x and y km/h heading directly towards each other across a distance of 960 km. If both start at 10 am they will meet at 3 pm. If Murray starts at 6 am and Mary starts at 10 am they will meet at noon. Find (x,y)
5x + 5y = 960____5(x + y) = 5(192)______x + y = 192 ------- eq (i)
2x + 6y = 960____2(x + 3y) = 2(480)_____x + 3y = 480 ------ eq (ii)
2y = 288 ------- Subtracting eq (i) from eq (ii)
You should also get: 
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