SOLUTION: The equation, in general form, of the line that passes through the point (3,5) and is parallel to the line 6x-9y+2=0 is Ax+By+C=0 where A,B and C are what?

Question 993988: The equation, in general form, of the line that passes through the point (3,5) and is parallel to the line 6x-9y+2=0 is Ax+By+C=0 where A,B and C are what?
Found 2 solutions by josgarithmetic, anand429:
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
A study about that STANDARD form equation format would help you to understand or be able to determine that the slope is . Your given line accordingly has a slope . You find the value for C using the point (3,5) which must be on the line parallel to the given line.

Be careful. The original given line is 6x-9y+2=0, and using this, the slope is also , so you might want to stay with the less simplified form just to avoid complicating mistakes if you want.

Parallel lines in the plane has equal slopes, so the line you are trying to find will also have slope .

Staying in STANDARD FORM, the equation you want will be .

.

Values for A and B were already explained and shown.

Your description mentioned "general form" at the beginning. If you want that, then solve for y from . Notice that if you simplify this standard form equation it is . Using this simplified form of the standard form equation, you have .
Answer by anand429(138) (Show Source): You can put this solution on YOUR website!
For parallel lines:
A1/A2 = B1/B2
So,
=> -3A=2B ----------------------------(i)
Now it passes through (3,5) so,
A*3 +B*5 +C=0
=> 3A+5B + C=0
=> 3B = -C (using (i))-----------(ii)
Simplfying given equation in terms of single variable we get,
Ax+By+C=0
=>
=>
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