SOLUTION: The perimeter of a rectangle is 32in. If the length of the rectangle is 1 more than twice the width. Find the dimensions of the rectangle .
Algebra.Com
Question 993404: The perimeter of a rectangle is 32in. If the length of the rectangle is 1 more than twice the width. Find the dimensions of the rectangle .
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Hi there,
Make the width = 'x'
Length = 1 + 2x
Perimeter = 2 x Width + 2 x Length
32 = 2(x) + 2(1 + 2x)
32 = 2x + 2 + 4x
Collect like terms.
2x + 4x = 32 - 2
6x = 30
x = 5
Width = 5 in
Length = 11 in
Hope this helps :-)
RELATED QUESTIONS
The perimeter of a rectangle is 62 cm. The length of the rectangle is 1 cm more than... (answered by ewatrrr)
The length of a rectangle is 2 in. more than twice its width. If the perimeter of the... (answered by checkley71)
The length of a rectangle is 2 in. more than twice its width. If the
perimeter of the... (answered by weepingwillowcats)
The length of a rectangle is 2cm more than twice its width. If the perimeter of the... (answered by Nate)
The length of a rectangle is 2 cm more than twice its width. If the perimeter of the... (answered by aaaaaaaa)
The length of a rectangle is 2 in. more than twice its width. If the perimeter of the... (answered by Nate)
The length of a rectangle is 3in. more than twice its width. If the perimeter of the... (answered by checkley71)
The length of a rectangle is 2 cm more than twice its width. If the perimeter of the... (answered by Juhi,Niku)
The length of a rectangle is 2 cm more than twice its width. If the perimeter of the... (answered by checkley71)