SOLUTION: How do you solve
x+3y=18
-2x + 5y= -3
So far I did 3y=-x+18
And started to divide each by 3...
3y/3 = -x/3 + 18/3
Y= -1/3x + 6
Y-6= -1/3x
Do I divide both sides by -1
Algebra.Com
Question 991541: How do you solve
x+3y=18
-2x + 5y= -3
So far I did 3y=-x+18
And started to divide each by 3...
3y/3 = -x/3 + 18/3
Y= -1/3x + 6
Y-6= -1/3x
Do I divide both sides by -1/3?
Now I'm stuck... Can you please help me?
Answer by ikleyn(52802) (Show Source): You can put this solution on YOUR website!
.
.
Express x from the first equation, x = 18-3y, and substitute it into the second equation. You will get
-2*(18-3y) + 5y = -3.
Simplify and solve it:
-36 + 6y + 5y = -3,
11y = -3 + 36,
11y = 33,
y = = 3.
Then x = 18 -3y = 18 - 3*3 = 18 - 9 = 9.
Answer. x=9, y=3.
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