SOLUTION: Solve the inequality x^2-4+(3/x)< 0 What I have tried: (x^3-4x+3)/x < 0 I do not know how to proceed after this. Thank you in advance

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Question 981172: Solve the inequality
x^2-4+(3/x)< 0
What I have tried:
(x^3-4x+3)/x < 0
I do not know how to proceed after this.
Thank you in advance

Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!


and your correct step giving



This inequality has possibly four critical x values:
0, and whatever are the "roots" of the numerator.

Rational Roots Theorem and Synthetic Division will give only as factor, and then quadratic factor will have roots ;
The other zero is 0, for which the equation is undefined.

Check any value within these five intervals:
(-infinity, -2.3025), the right limit being decimal approximation for irrational;
(-2.3025,0);
(0,1);
(1, 1.3025), again right limit is decimal approximation;
(1.3025, infinity).

Find if the value in the interval makes the original inequality true or false.


Here is a graph of the left member just as a check for your efforts checking in each interval.


A close-up of one area of the graph:


--
What you should find:
(-infinity, -2.3025), False
(-2.3025,0), True;
(0,1), False;
(1, 1.3025), True;
(1.3025, infinity), False

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