SOLUTION: Write the equation of the line with the given conditions Passing through (1,-6) and perpendicular to the line with equation -2x+3y=-16 A) y=-3/2x+9/2 B) y=-2/3x-2/3 C)

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Question 980930: Write the equation of the line with the given conditions
Passing through (1,-6) and perpendicular to the line with equation -2x+3y=-16
A) y=-3/2x+9/2
B) y=-2/3x-2/3
C) y=-1/3x+16/3
D) y=3/2x+9/2
Found 3 solutions by josgarithmetic, MathTherapy, solver91311:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Any line perpendicular to would be some ; and if this line contains or passes through (1,-6), then , or .

To find the correct choice, solve the resulting equation for y.

Understanding Standard Form Equation for a line is very helpful.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Write the equation of the line with the given conditions
Passing through (1,-6) and perpendicular to the line with equation -2x+3y=-16
A) y=-3/2x+9/2
B) y=-2/3x-2/3
C) y=-1/3x+16/3
D) y=3/2x+9/2
- 2x + 3y = - 16

3y = 2x - 16



, or  

With , and point (1, - 6), we get: 

 





 <--------- NONE OF THE CHOICES 

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!
 





Perpendicular lines have slopes that are negative reciprocals.  Put the given equation into slope-intercept form, find the slope of the given line, then take the negative reciprocal of that slope. Since the four given answers all have different slopes, you don't need to bother finding the intercept for the desired equation.





John



My calculator said it, I believe it, that settles it



 

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