SOLUTION: how to find the equation of the perpendicular bisector of the line segment with endpoints (-6,-1) & (6,7)
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Question 975595: how to find the equation of the perpendicular bisector of the line segment with endpoints (-6,-1) & (6,7)
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
slope is 7-(-1)/6-(-6) or 8/12 or 2/3. The midpoint is the average of the x s and the average of the ys
That is (0,3)
the first two points have and equation of a line between them of
y-7 = (2/3)( x-6) or y-7=(2x/3)-4; y=(2x/3) +3
perpendicular line's slope is negative reciprocal or -3/2
point slope formula using midpoint, which is (0,3), the midpoint of the x s and y s
y-3= (-3x/2)
y=-(3/2)x +3
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