SOLUTION: You want 40 liters of 60% solution. How much 80% solution and how much 28% solution must you mix to produce that result? (Round to nearest hundredth.)

SOLUTION: You want 40 liters of 60% solution. How much 80% solution and how much 28% solution must you mix to produce that result? (Round to nearest hundredth.)

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Question 97081: You want 40 liters of 60% solution. How much 80% solution and how much 28% solution must you mix to produce that result? (Round to nearest hundredth.)
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
.6*40=.8x+.28(40-x)
24=.8x+11.2-.28x
.8x-.28x=24-11.2
.52x=12.8
x=12.8/.52
x=24.62 liters of the80% solution is needed.
40-24.62=15.38 liters of the 28% solution is needed.
proof
24=.8*24.62+.28*15.38
24=19.69+4.31
24=24

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