Im not sure if this question belongs in this section so please forgive me if it isn't but I just don't know where to start with this equation.
"Find the equation of the line through (1,3) that is parallel to the line 6x+10y+1=0"
Please help me with step by step action because as you can probably tell I have no idea what to do, and a teacher who speeds way past my ability to comprehend. Thank you in advance, the help is much appreciated.
y = mx + b ------- Slope-intercept form of a linear equation
(x, y) being a point on the line, m is the slope, and b is the y-intercept
Your equation: 6x + 10y + 1 = 0
10y + 1 = - 6x ------ Subtracting 6x
10y = - 6x - 1 ------ Subtracting 1
Slope of above equation:
Since parallel lines have congruent slopes, slope of new line, or
Point on line to be formed: (1, 3)
------ Point-slope form
------ Substituting values
------ Adding 3 to both sides
----- Equation being sought