SOLUTION: I am trying to solve and graph 3(X+1)^2+3(y-1)^2=6
I came up with 1,-1) radius 1.4142 but I think it might be backwards.
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Question 96953: I am trying to solve and graph 3(X+1)^2+3(y-1)^2=6
I came up with 1,-1) radius 1.4142 but I think it might be backwards.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
3(X+1)^2+3(y-1)^2=6
Divide thru by 3 to get:
(x+1)^2 + (y-1)^2 = 2
Circle with center at (-1,1)
Radius = sqrt(2)= 1.414...
cheers,
Stan H.
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