SOLUTION: 1. Graph the line y=-3/2x 2. Graph the line y=-4/3x - 4 using only slope and y intercept

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Question 96498: 1. Graph the line y=-3/2x
2. Graph the line y=-4/3x - 4 using only slope and y intercept

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
These explanations are quite long, so here is a table of contents


Problem #1
Problem #2





#1

The equation really looks like

Solved by pluggable solver: Graphing Linear Equations
In order to graph we only need to plug in two points to draw the line

So lets plug in some points

Plug in x=-6



Multiply

Add

Reduce

So here's one point (-6,9)




Now lets find another point

Plug in x=-4



Multiply

Add

Reduce

So here's another point (-4,6). Add this to our graph





Now draw a line through these points

So this is the graph of through the points (-6,9) and (-4,6)


So from the graph we can see that the slope is (which tells us that in order to go from point to point we have to start at one point and go down -3 units and to the right 2 units to get to the next point), the y-intercept is (0,)and the x-intercept is (,0)


We could graph this equation another way. Since this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,).


So we have one point (0,)





Now since the slope is , this means that in order to go from point to point we can use the slope to do so. So starting at (0,), we can go down 3 units



and to the right 2 units to get to our next point


Now draw a line through those points to graph


So this is the graph of through the points (0,0) and (2,-3)



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#2


Since this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,).

So we have one point (0,)



Now since the slope is , this means that in order to go from point to point we can use the slope to do so. So starting at (0,), we can go down 4 units


and to the right 3 units to get to our next point

Now draw a line through those points to graph

So this is the graph of through the points (0,-4) and (3,-8)

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