The converse of the Pythagorean theorem is also a true statement: If the sum of the squares of the lengths of two sides of a triangle is is equal to the square of the length of the third side, then the triangle is a right triangle. Use the distance formula and the Pythagorean theorem to determine whether the set of points could be vertices of a right triangle.
(-3,1),(2,-1) and (6,9)
How is this problem solved? Please show all the steps clearly. Thank you.
First plot the points and draw the triangle so
you can tell which one looks most like the
vertex of a right angle.
Well, from looking at that picture the angle
at (2,-1) looks the most like a right angle.
So if this is really a right triangle, that
would make the hypotenuse be the side connecting
the points (-3,1) and (6,9), so we use the
formula for the distance between two points to
calculate the hypotenuse:
__________________
D = Ö(x2-x1)² + (y2-y1)²
with (x1,y1) = (-3,1) and (x2,y2) = (6,9)
__________________
D = Ö(6-(-3))² + (9-1)²
___________
D = Ö(6+3)² + 8²
_______
D = Ö9² + 8²
_______
D = Ö81 + 64
___
D = Ö145 = hypotenuse
Now we find the shorter leg, which connects
the point (-3,1) to the point (2,-1)
__________________
D = Ö(x2-x1)² + (y2-y1)²
with (x1,y1) = (-3,1) and (x2,y2) = (2,-1)
__________________
D = Ö(2-(-3))² + (-1-1)²
______________
D = Ö(2+3)² + (-2)²
______
D = Ö5² + 4
______
D = Ö25 + 4
__
D = Ö29 = shorter leg
Now we find the longer leg, from
(-2,1) to (6,9)
__________________
D = Ö(x2-x1)² + (y2-y1)²
with (x1,y1) = (-2,1) and (x2,y2) = (6,9)
Ö
__________________
D = Ö(6-2)² + (9-(-1))²
___________
D = Ö4² + (9+1)²
________
D = Ö16 + 10²
________
D = Ö16 + 100
___
D = Ö116 = longer leg
So we see if this Pythagorean equation holds:
?
(hypotenuse)² = (shorter leg)² + (longer leg)²
___ ? __ ___
(Ö145)² = (Ö29)² + Ö116)²
?
145 = 29 + 116
Ö
145 = 145
So, yes, the Pythagorean equation holds so,
it is a right triangle
Edwin