SOLUTION: How do I graph the following equations 1. 8y=3x+16, 2. 25x+30y=120 Write an equation in slope-intercept form for the line that contains the given points. 1.(2,10) and (3,35) 2.

Question 94529: How do I graph the following equations 1. 8y=3x+16, 2. 25x+30y=120
Write an equation in slope-intercept form for the line that contains the given points. 1.(2,10) and (3,35) 2. (-3,0) and(2,2) 3. (-2,5.5) and (0.5,-2)
Please help, I don't understand this at all!!
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
8Y=3X+16 OR Y=3X/8+16/8 OR Y=3X/8+2 (RED LINE)
25X+30Y=120 OR 30Y=-25X+120 OR Y=-25X/30+120/30 OR Y=-5X/6+4 (GREEN LINE)
(graph 300x200 pixels, x from -6 to 5, y from -10 to 10, of TWO functions y = 3x/8 +2 and y = -5x/6 +4).
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(2,10) & (3,35) give a slope of:
(y2-y1)/(x2-x1)
(35-10)/(3-2)
25/1=25 for the slope.
now substitute 1 set of (x,y) values in the line equation [Y=mX+b] & SOLVE FOR THE Y INTERCEPT (b).
-2=25*3+b
-2+75+b
b=-2-75
b=-77
THUS THE EQUATION FOR A LINE THROUGH THESE 2 POINTS IS:
Y=25X-77
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I'LL LEAVE THE REST FOR YOU TO SOLVE NOW THAT i'VE SHOWN YOU HOW TO CALCULATE THE SLOPE (m) & THE Y INTERCEPT (b).
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